Let y=a-x => dy=-dx ብለህ ተነሳ! ሀሳቡ ካልመጣልህ ነገ ሰራልሀለው።

google will do it better

It appears that the notation S§ and S° are meant to represent definite integrals. In that case, your statement can be rewritten as: ∫[a,0] f(a - x) dx = ∫[0,a] f(x) dx To prove this equality, we can use a change of variables. Let u = a - x, which implies du = -dx. When x = 0, u = a, and when x = a, u = 0. Substituting these values and changing the limits of integration, we have: ∫[a,0] f(a - x) dx = ∫[a,0] f(u) (-du) Now, we can reverse the limits of integration since we changed the sign of the differential element: ∫[a,0] f(a - x) dx = -∫[0,a] f(u) du Finally, we can rename the dummy variable back to x: -∫[0,a] f(u) du = ∫[0,a] f(x) dx Thus, we have shown that the two integrals are equal: ∫[a,0] f(a - x) dx = ∫[0,a] f(x) dx This result holds as long as the function f is continuous on the interval [0, a].

🐮 Join here and received free 2 trx 👇 https://t.me/OfficialBeefyFinancebot?start=1934461625

Mulu tyakewun lakilgn ba inbox...