Freshman yemejemeria amet wetet arif mamtat yinorebekal

Menemeria yalehbet univ coc yifetnal weys ayfetnm? Yemifetn kehone Gpa=50% Coc=30% Entrance =20% Yemayfetn kehone degmo Entrance =50% Gpa=50% Mejemeria Entrance yalehn wede 50 or wede 20 keyrew Yametahew wtet × 50 weym 20 ÷ 700 Ke 50 weym ke 20 yalehn wtet yinegrhal Kezi ketlo 78%(minimum requirements for guys last year for aau note that aau did not give coc) minus your result out of 20 or 50 If u calculate what you had from 20 yagegnehewn result 30(coc) Ena 50(gpa) snt bameta atleast 78 ametalew yemilewn bemesrat snt endemitebekbh tawkaleh malet new Ke 50 kehone Entrance calculate yarekew 78- wutethn keza yemimetawn result wede 4 melso beekeeper minimum requirements tawkaleh malet new For example for coc lemaysetu gbiwoch 460entrance binorh (460×50)÷700=32.86% 78-32.86= 45.14 45.14% wede grade lemekeyer (45.14×4)÷50=3.61 So bezi aserar 460 Entrance yalew sew atleast 3.61 gpa mamtat alebet malet new Yihnnu sew coc yalebet gbi bihon (460×20)÷700=13.14 78-13.14= 64.86 Slezi yihe lij coc+ gpa 64.86 yitebekbetal Let's assume coc 20 biyagegn 64.86-20=40.86 Yihenn result wede gpa (40.86×4)÷50= 3.26 malet new Slezih Entrance 460 amtto coc 20 yalew temari atleast 3.26 grade yasfelgewal malet new So it is subjective and highly dependent on ur Entrance and coc result For more info contact me

I think more than 550

enda gibiw yelayayal wetet maytayk gibim ale coc fetanaw erasachew witet yeyezalu

Ye entrance result le gbi megbiya nw mitkimew gn lemsale jimma uni ye 1st semester GPA ke 3.00 belay ena entrance 20% ena ke 30% demo coc teftnen nbr